STA641 GDB No 2 Solution Spring 2020-VU-Digilearnerspoint


STA641 GDB No 2 Solution 2020-Spring Semester-VU-Statistical Packages and its Applications

STA641 GDB No 2 Solution Spring 2020-VU-Digilearnerspoint, statistical packages and its application
STA641 GDB No 2 Solution Spring 2020 of VU has been presented by Digilearnerspoint in this video tutorial that gives a lot of assistance solving GDB

Starting Date: 28-08-2020

Closing Date: 02-09-2020

Question Discussion/Scenario

Question Instructions

  1. Enter or Copy/Paste the given question data into SPSS.
  2. Then, apply the appropriate functions/calculations to get the required results
  3. In the end, Copy/Paste your relevant answers/results/graph into GDB answer/reply Section

Which tool you should use?

You need to use SPSS Application to solve this question.

Question Data

Perform the Analysis of Variance (ANOVA) for the given data and test the :

Null Hypothesis:                                 Ho=All factors are the same

Alternative Hypothesis:                      H1=All factors are not the same

After Analysis

  1. Report/show your results. Highlights key values/findings
  2. Show/Highlight Mean and Standard Deviation for each of the factor
  3. What is the computed F-test Value?
  4. From your results, can we accept or reject the null hypothesis?

DATA TABLE 

STA641 GDB 2 Solution 2020, Degree of freedom


According to the F significance/probability with df = (2,21) F must be at least 3.4668 to reach p<0.05, so F score is statistically significant.

Solution

Given Information

alpha=p=0.05

F-test score= F(2,21) = 3.4668


One way

Descriptives
Responses

N
Mean
Std. Deviation
Std. Error
95% Confidence Interval for Mean
Minimum
Maximum
Lower Bound
Upper Bound
A
5
51.80
26.224
11.728
19.24
84.36
19
83
B
5
55.40
30.080
13.452
18.05
92.75
22
100
C
5
56.80
36.148
16.166
11.92
101.68
26
103
Total
15
54.67
28.863
7.452
38.68
70.65
19
103




Test of Homogeneity of Variances
Responses
Levene Statistic
df1
df2
Sig.
.820
2
12
.463

ANOVA
Responses

Sum of Squares
df
Mean Square
F
Sig.
Between Groups
66.533
2
33.267
.034
.966
Within Groups
11596.800
12
966.400


Total
11663.333
14




Conclusion

As Fc < FG that is 0.034 < 3.4668, therefore we reject the null hypothesis and inferred that the F score is statistically insignificant at the level of significance 0.05

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